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JAMB Chemistry 2019 Paper

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Question : 54

Total: 80

The electronic configuration of element Z is 1s

^{2}

^{2}

^{6}

^{2}

^{1}

. What is the formula of the compound formed between Z and tetraoxosulphate (VI) ion.

Z $_{3}$ (SO $_{4}$ ) $_{2}$
ZSO $_{4}$
Z $_{2}$ SO $_{4}$
Z $_{2}$ (SO $_{4}$ ) $_{3}$

Solution:

Z = 1s $^{2}$ 2s $^{2}$ 2p $^{6}$ 3s $^{2}$ 3p $^{1}$

$\therefore$ We have Z $^{3+}$ and SO $_{4}^{2-}$

The reaction : Z $^{3+}$ + SO $_{4}^{2-}$ $\to$ Z $_{2}$ (SO $_{4}$ ) $_{3}$ .

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