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JAMB Chemistry 2019 Paper

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Question : 51

Total: 80

What volume of 0.100M sodium trioxonitrate (V) solution contains 5g of solute.

[Na = 23, N = 14, O = 16]

1.7 litres
0.420 litres
0.588 litres
2.35 litres

Solution:

Concept:

Use

\text{Volume} = \frac{\text{moles of solute}}{\text{molarity}}

.

Explanation:

Sodium trioxonitrate (V) is

\mathrm{NaNO}_3

.

Molar mass of

\mathrm{NaNO}_3 = 23 + 14 + 3(16) = 85\ \mathrm{g\,mol^{-1}}

.

Moles of solute in

5\ \mathrm{g}

:

\text{moles} = \frac{5}{85} = 0.05882\ \mathrm{mol}

Volume of

0.100\ \mathrm{M}

solution:

\text{Volume} = \frac{0.05882}{0.100} = 0.588\ \mathrm{litres}

Answer:

0.588 litres — Option C.

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