Concept:Identify the valencies from the electronic configurations and combine them by criss-crossing charges.Explanation:X: 1s22s22p4 has 6 valence electrons, so it needs 2 more electrons: valency 2, charge X2−.Y: 1s22s22p63s23p1 has 3 valence electrons, so it can lose 3 electrons: valency 3, charge Y3+.To balance charges: 2×(+3)+3×(−2)=0.Thus, the formula is Y2X3.Answer:C. Y2X3