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JAMB Chemistry 2018 Paper

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Question : 8

Total: 87

To what temperature must a gas at 273k be heated in order to double both its volume and pressure?

298K
546K
819K
1092K

Solution:

Concept:

The combined gas law relates pressure, volume, and temperature of a fixed amount of gas.

Explanation:

Use the combined gas law:

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

.

Let the initial pressure and volume be

P_1

and

V_1

.

Doubling both gives:

P_2 = 2P_1

and

V_2 = 2V_1

.

So,

P_2V_2 = (2P_1)(2V_1) = 4P_1V_1

.

Therefore,

T_2 = 4T_1

.

Given

T_1 = 273\,K

, then

T_2 = 4 \times 273 = 1092\,K

.

Answer:

1092\,K

— Option D

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