(I). 3CuO (s) + 2NH 3(g) ----- 3Cu (s) + 3H 2 O (l) + N 2(g) (II). 2NH 3(g) + 3Cl 2(g) ----- 6HCl (g) + N 2(g) (III). 4NH 3(g) + 3O 2(g) ----- 6H 2 O (l) + N 2(g) The reactions represented by the equations above demonstrate the

Question

(I). 3CuO (s) + 2NH 3(g) -----> 3Cu (s) + 3H 2 O (l) + N 2(g) (II). 2NH 3(g) + 3Cl 2(g) -----> 6HCl (g) + N 2(g) (III). 4NH 3(g) + 3O 2(g) -----> 6H 2 O (l) + N 2(g) The reactions represented by the equations above demonstrate the

Africa Exams · Accepted Answer

Correct Answer is : reducing properties of ammonia

JAMB Chemistry 2018 Paper