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JAMB Chemistry 2015 Paper

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Question : 59

Total: 64

In the electrolysis of CuSo4(g) using platinum electrode the reaction at the anode is

4H+ 4e - 2H₂
4OH⁼ 4e- + 2H₂O + O₂
2OH - 2e_- = 2OH
2OH^- + 2OH = 2H₂O + O₂

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