JAMB Chemistry 2014 Paper

Concept:For a halogenated alcohol, choose the longest chain containing $\mathrm{-OH}$, number from the end nearest $\mathrm{-OH}$, and list substituents alphabetically.Explanation:The parent chain is a four-carbon alcohol, so it is butan-1-ol.Numbering from the $\mathrm{-OH}$ end places chloro at C-2 and bromo at C-3.IUPAC lists substituents alphabetically: bromo ($\mathrm{Br}$) before chloro ($\mathrm{Cl}$).Therefore, the name is 3-bromo-2-chlorobutan-1-ol.Answer:B. 3-bromo-2-chlorobutanol