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JAMB Chemistry 2013 Paper

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Question : 43

Total: 44

Zn_(s) + CuSO_4(aq)

\to

ZnSO_4(aq) + Cu_(s)

In the reaction above, the oxidizing agent is

CuSO_4(aq)
ZnSO_4(aq)
Cu_(s)
Zn_(s)

Solution:

Concept:

The oxidizing agent is the species that is reduced (gains electrons).

Explanation:

In the reaction,

\mathrm{Zn}

changes from

0

to

+2

in

\mathrm{ZnSO_4}

, so it is oxidized.

\mathrm{Cu^{2+}}

in

\mathrm{CuSO_4}

changes from

+2

to

0

in

\mathrm{Cu}

, so it is reduced.

Since

\mathrm{CuSO_4}

is reduced, it acts as the oxidizing agent.

Answer:

A.

\mathrm{CuSO}_{4(aq)}

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