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JAMB Chemistry 2012 Paper

Question : 16

Total: 45

[K = 39, Cl = 35.5 O =16]

Solution:

Concept:

The mass crystallized when the solution cools equals the decrease in solubility multiplied by the molar mass of

\mathrm{KClO}_3

Explanation:

Solubility decrease =

1.5 - 0.5 = 1.0\ \mathrm{mol\ dm}^{-3}

Assume

1\ \mathrm{dm}^3

of solution, so amount crystallized =

1.0\ \mathrm{mol}

Molar mass of

\mathrm{KClO}_3

39 + 35.5 + 3(16) = 122.5\ \mathrm{g\ mol}^{-1}

Mass crystallized =

1.0 \times 122.5 = 122.50\ \mathrm{g}

Answer:

122.50\ \mathrm{g}

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