with conc H 2 SO 4 as catalyst CH 3 COOH + C 2 H 5 OH → CH 3 COOC 2 H 5 + H 2 O

Correct Answer is : esterification

Correct Answer is : esterification

Test Index

JAMB Chemistry 2011 Paper

Question : 44

Total: 47

with conc H₂SO₄ as catalyst

CH₃COOH + C₂H₅OH → CH₃COOC₂H₅ + H₂O

Solution:

Concept:

A carboxylic acid reacts with an alcohol to form an ester and water in the presence of a strong acid catalyst.

Explanation:

The reaction is:

\mathrm{CH_3COOH} + \mathrm{C_2H_5OH} \xrightarrow{\mathrm{conc.\ H_2SO_4}} \mathrm{CH_3COOC_2H_5} + \mathrm{H_2O}

Acetic acid,

\mathrm{CH_3COOH}

, reacts with ethanol,

\mathrm{C_2H_5OH}

, to produce ethyl acetate,

\mathrm{CH_3COOC_2H_5}

, and water.

This is the process of forming an ester, hence it is called esterification.

Answer:

A. esterification

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