CH 3 COOH (aq) + OH - (aq) ↔ CH 3 COO - (aq) + H 2 O (l) In the reaction above ,CH 3 COO - (aq) is

Correct Answer is : conjugate base

Correct Answer is : conjugate base

Test Index

JAMB Chemistry 2011 Paper

Question : 16

Total: 47

In the reaction above ,CH₃COO^-_(aq) is

Solution:

Concept:

An acid that loses a proton forms its conjugate base.

Explanation:

In the reaction,

\mathrm{CH_3COOH}

donates a proton

(\mathrm{H^+})

\mathrm{OH^-}

The product

\mathrm{CH_3COO^-}

is what remains after

\mathrm{CH_3COOH}

has lost that proton.

Therefore,

\mathrm{CH_3COO^-}

is the conjugate base of

\mathrm{CH_3COOH}

Answer:

A. conjugate base

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