Calcium trioxonitrate(V) is (CaNO3)2
The molecular mass of Ca(NO3)2 = 40 + (14 + (16 X 3)) x 2 = 164
Relative molecular mass of nitrogen(N) = 14 x 2 = 28
% by mass of nitrogen in Ca(NO3)2 = \(\frac{28}{164} x \(\frac{100}{1}
= 17.073 ≈ 17.1
