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JAMB Chemistry 2010 Paper

Question : 14

Total: 49

[Cu = 64, S = 32, O = 16]

Solution:

Concept:

Solubility is the number of moles of solute dissolved in

1\,\text{dm}^3

of solution.

Explanation:

Here,

100\,\text{g}

of water is taken as the solvent volume because the density of water is about

1\,\text{g cm}^{-3}

So,

100\,\text{g}

of water

= 100\,\text{cm}^3 = 0.1\,\text{dm}^3

Calculate the molar mass of

\mathrm{CuSO}_4

64 + 32 + (4 \times 16) = 160\,\text{g mol}^{-1}

Moles of

\mathrm{CuSO}_4

40\,\text{g}

\frac{40}{160} = 0.25\,\text{mol}

Solubility

= \frac{\text{moles}}{\text{volume in dm}^3} = \frac{0.25}{0.1} = 2.5\,\text{mol dm}^{-3}

Answer:

2.50\,\text{mol dm}^{-3}

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