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BECE Mathematics 2024 Paper

Question : 28

Total: 40

4,7,10,\dots

Solution:

Concept:

The distances form an arithmetic sequence with a common difference of

3

Explanation:

The given sequence is

4, 7, 10, \dots

Here, first term

a = 4

and common difference

d = 7 - 4 = 3

For the

n

th term of an arithmetic sequence:

T_n = a + (n-1)d

For the 10th leap,

n = 10

T_{10} = 4 + (10-1) \times 3

T_{10} = 4 + 9 \times 3 = 4 + 27

T_{10} = 31

Answer:

The distance after the 10th leap is

31

m, i.e., Option B.

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