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BECE Mathematics 2023 Paper

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Question : 7

Total: 40

If

n(=15, n(F)=20

n(E \cap F)=6

n(E \cup F)

21
26
29
35

Solution:

Concept:

Use the set inclusion-exclusion formula:

n(E \cup F) = n(E) + n(F) - n(E \cap F)

.

Explanation:

Given

n(E) = 15

,

n(F) = 20

, and

n(E \cap F) = 6

.

Substitute these values into the formula:

n(E \cup F) = 15 + 20 - 6

= 35 - 6 = 29

.

So the total number of elements in the union of sets

E

and

F

is

29

.

Answer:

C.

29

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