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BECE Mathematics 2021 Paper

Question : 30

Total: 40

36\;\mathrm{cm}^2

Solution:

Concept:

The area of a trapezium equals half the sum of the parallel sides multiplied by the distance between them (the height).

Explanation:

Let the parallel sides be

a = 10.5\;\mathrm{cm}

and

b = 9.5\;\mathrm{cm}

Area of trapezium

= \frac{1}{2}(a + b) \times h

Here,

a + b = 10.5 + 9.5 = 20\;\mathrm{cm}

So,

\frac{1}{2} \times 20 \times h = 10h

Given area

= 36\;\mathrm{cm}^2

Therefore,

10h = 36

Divide both sides by 10:

h = \frac{36}{10} = 3.6\;\mathrm{cm}

Thus, the distance between the parallel sides is

3.6\;\mathrm{cm}

Answer:

\;\;3.6\;\mathrm{cm}

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