BECE Mathematics 2021 Paper

Concept:Factorize by grouping terms that have common factors, then take out the common binomial factor.Explanation:Consider the expression:$3 a x+6 a-x-2$.Rewrite it by grouping the first two terms and the last two terms:$(3 a x+6 a)+(-x-2)$.From $3 a x+6 a$, the common factor is $3a$, so it becomes:$3a(x+2)$.From $-x-2$, the common factor is $-1$, so it becomes:$-1(x+2)$.Therefore, the full expression is:$3a(x+2)-1(x+2)$.Now $(x+2)$ is common in both terms, so we factor it out:$(x+2)(3a-1)$.Since the order of multiplication does not matter, this is equal to:$(3a-1)(x+2)$.Answer:D. $(3a-1)(x+2)$