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BECE Mathematics 2015 Paper
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© africaexams.com
Question : 5
Total: 40
Find the Highest Common Factor of 24, 42 and 72
4
6
7
12
Validate
Solution:
Prime factors of 24
Prime factors
=
2
×
2
×
2
×
3
=
2
3
×
3
Prime factors of 42
Prime factors
=
2
×
3
×
7
Prime factors of 72
Prime factors
=
2
×
2
×
2
×
3
×
3
=
2
3
×
3
2
Common prime factors are 2 and 3
The H.C.F is the product of each of the common prime factors in their lowest power
=
2
×
3
=
6
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