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BECE Mathematics 2015 Paper

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Question : 29

Total: 40

A rectangular field 50 m wide and

y m

long requires 260 m of fencing. Find

y

15 m
40 m
80 m
105 m

Solution:

Concept:

The fencing required equals the perimeter of the rectangular field.

Explanation:

For a rectangle, perimeter

= 2(\text{length} + \text{width})

.

Here, width

= 50

m and length

= y

m.

So, perimeter

= 2(50 + y) = 100 + 2y

.

Given that the fencing needed is

260

m, we set:

100 + 2y = 260

Subtract

100

from both sides:

2y = 160

Divide both sides by

2

:

y = 80

m

Answer:

y = 80

m, which is option C.

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