Find the value of n, if 25.003=(2 × 10)+(5 × 1)+(3 × n)

Correct Answer is : 0.0010.0010.001

Correct Answer is : 0.0010.0010.001

Test Index

BECE Mathematics 2015 Paper

Question : 20

Total: 40

n

25.003=(2 \times 10)+(5 \times 1)+(3 \times n)

Solution:

The

3 \times n

is in the place of the decimal place value.

3 \times n=0.003

Divide both sides of the equation by 3

\; n=\; \frac{0.003}{3}

\;0.003=0.001 \times 3

\; n=\; \frac{0.001 \times 3}{3}

\; n=0.001

Alternate Solution

You can as well solve for the value of

n

in the equation and obtain the same answer

\; 25.003=(2 \times 10)+(5 \times 1)+(3 \times n)

\;2 \times 10=20

\;5 \times 1=5

\;25.003=20+5+(3 \times n)

\;25.003=25+(3 \times n)

\;25.003-25=(3 \times n)

\;0.003=3 \times n

Divide both sides of the equation by 3

\;\; \frac{0.003}{3}=n

\;0.003=0.001 \times 3

\;\; \frac{0.001 \times 3}{3}=n

\;0.001=n

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