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BECE Mathematics 2013 Paper

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Question : 5

Total: 40

Given that

A = \{a, e, i, o, u\}

B = \{r, s, t\}

, how many elements are in

A \cap B

0
1
2
3

Solution:

Concept:

The intersection

A \cap B

contains only elements that are present in both sets

A

and

B

.

Explanation:

Set

A = \{a, e, i, o, u\}

.

Set

B = \{r, s, t\}

.

Compare the two sets: no letter appears in both sets.

Therefore,

A \cap B = \varnothing

or

\{\}

.

An empty set has

0

elements.

So the number of elements in

A \cap B

is

0

.

Answer:

Option A:

0

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