Test Index

BECE Mathematics 2013 Paper

Question : 14

Total: 40

A(3,5)

B(-2,3)

Solution:

Concept:

The gradient of a straight line is the ratio of the change in

y

to the change in

x

between two points.

Explanation:

For points

A(3,5)

and

B(-2,3)

, use the formula:

\text{Gradient} = \frac{y_2 - y_1}{x_2 - x_1}

Let

(x_1, y_1) = A(3,5)

and

(x_2, y_2) = B(-2,3)

So,

y_2 = 3

y_1 = 5

x_2 = -2

, and

x_1 = 3

Substitute these values:

\text{Gradient} = \frac{3 - 5}{-2 - 3} = \frac{-2}{-5}

Since the negative signs cancel, the gradient is:

\frac{2}{5}

Answer:

\frac{2}{5}

This matches option B.

Go to Question:

Prev Question

Next Question