Concept:In an isosceles triangle, the base angles are equal.Also, the sum of angles in a triangle is 180∘.Explanation:Given PS=SQ, so triangle SPQ is isosceles.Hence, ∠SPQ=∠SQP.At point Q, ∠SQP and ∠SQR=112∘ lie on a straight line.So, ∠SQP+112∘=180∘.Thus, ∠SQP=180∘−112∘=68∘.Therefore, ∠SPQ=68∘.Let x=∠QSP.Using the angle sum of triangle SPQ:68∘+68∘+x=180∘136∘+x=180∘x=180∘−136∘=44∘.Answer:x=44∘, which is option D.