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BECE Mathematics 2010 Paper

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Question : 19

Total: 40

Eighteen cards are numbered from 11 to 29. If one card is chosen at random, what is the probability that it contains the digit 2?

$\frac{3}{9}$
$\frac{7}{18}$
$\frac{5}{9}$
$\frac{11}{19}$

Solution:

Concept:

Probability is the ratio of favourable outcomes to total possible outcomes.

Explanation:

The cards are numbered from 11 to 29.

Inclusive count:

29 - 11 + 1 = 19

.

So, total possible outcomes

= 19

.

The numbers containing digit 2 are:

12, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29

.

Number of favourable outcomes

= 11

.

Required probability

= \frac{11}{19}

.

Answer:

Option D:

\frac{11}{19}

.

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