( 12−3\frac{1}{2 - \sqrt{3}}2−31 + 22+3\frac{2}{2 + \sqrt{3}}2+32 )−1^{-1}−1
= 2+3+2(2−3)(2−3)(2+3)\frac{2 + \sqrt{3} + 2(2 - \sqrt{3})}{(2 - \sqrt{3})(2 + \sqrt{3})}(2−3)(2+3)2+3+2(2−3)
= 2 + √3 + 4 - 2√3
= (6 - √3)−1^{-1}−1
= 16−3\frac{1}{6 - \sqrt{3}}6−31
= 6+3(6−3)(6+3)\frac{6 + \sqrt{3}}{(6 - \sqrt{3})(6 + \sqrt{3})}(6−3)(6+3)6+3
= 6+333\frac{6 + \sqrt{3}}{33}336+3
