logy 18=3 ⟹ y3=18\log_{y}\;\frac{1}{8} = 3 \implies y^{3} = \frac{1}{8}logy81=3⟹y3=81 (Laws of logarithm)
y3=123=(12)3y^{3} = \frac{1}{2^{3}} = \left(\frac{1}{2}\right)^{3}y3=231=(21)3
Equating both sides, we have
y=12y = \frac{1}{2}y=21