His movements 1km due east and then 1 km due north make a Right-Angled Triangle.
Using Pythagoras' theorem;
The Resultant becomes the Hypotenuse [h]
Hyp 2^{2}2 = Adj2+Opp2^{2} + \text{Opp}^{2}2+Opp2
Hyp2^{2}2 = 12^{2}2 + 12^{2}2
Hyp2^{2}2 = 2 → Hyp = √2
: Resultant = √2
DIRECTION TAN Ø = OPPADJ\frac{\text{OPP}}{\text{ADJ}}ADJOPP
TAN Ø = 11\frac{1}{1}11
Ø = TAN −1^{-1}−1 [1]
Ø= 45°
Displacement is √2km N 45°E
