Test Index

BECE Mathematics 2020 Paper

Question : 1

Total: 40

Simplify

\frac{3}{4} - \frac{1}{3} + \frac{1}{12}

Solution:

Concept:

To add or subtract unlike fractions, first rewrite them with a common denominator.

Explanation:

The denominators are

4

3

, and

12

The least common multiple (LCM) of

4

3

, and

12

12

Rewrite each fraction with denominator

12

\frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12}

-\frac{1}{3} = -\frac{1 \times 4}{3 \times 4} = -\frac{4}{12}

+\frac{1}{12} = +\frac{1}{12}

Now combine the numerators:

\frac{9}{12} - \frac{4}{12} + \frac{1}{12} = \frac{9 - 4 + 1}{12}

= \frac{6}{12}

Simplify by dividing numerator and denominator by

6

\frac{6 \div 6}{12 \div 6} = \frac{1}{2}

Answer:

\frac{1}{2}

So, the correct option is B.

\frac{1}{2}

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