BECE Mathematics 2012 Paper

Concept:The intersection of two sets contains only the elements that are common to both sets.Explanation:We are given $P=\{2,3,5,7\}$ and $Q=\{2,4,6,8\}$.List the elements of $P$: $2,3,5,7$.List the elements of $Q$: $2,4,6,8$.Find the elements that appear in both sets.The element $2$ is present in both $P$ and $Q$.The elements $3,5,7$ are only in $P$, and $4,6,8$ are only in $Q$.Therefore, the common element set is $\{2\}$.Answer:$P \cap Q = \{2\}$So the correct option is A. $\{2\}$.